লসাগু নির্ণয়ের সি প্রোগ্রাম | LCM Calculation in Programming [ HSC ICT Chapter-5]

 Solution 1

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//C program to find LCM of two numbers

#include <stdio.h>

int main()

{

    int Num1, Num2, max_Value;

    printf("Please Enter two integer Values \n");

    scanf("%d %d", &Num1, &Num2);

    max_Value = (Num1 > Num2)? Num1 : Num2;

    while(1) //Alway True

    {

    if(max_Value % Num1 == 0 && max_Value % Num2 == 0)

    {

    printf("LCM of %d and %d = %d", Num1, Num2, max_Value);

    break;

}

++max_Value;

}

    return 0;

}

 Solution 2

#include<stdio.h>

main()

{

    int num1,num2,gcd,temp,a,b,lcm;

    printf("Enter first number?");

    scanf("%d",&num1);

        printf("Enter second number?");

    scanf("%d",&num2);

    a=num1;

    b=num2;

    for(;b>0;)

    {

        temp=b;

        b=a%b;

        a=temp;

    }

    gcd=a;

    lcm=(num1*num2)/gcd;

    printf("\n Least common divisor of %d and %d= %d",num1,num2,lcm);

    return 0;

}

Solution-3

#include <stdio.h>

int main()

{

    int a, b, x;

    printf("Enter the first integer number: \n");

    scanf("%d", &a);

    printf("Enter the second integer number: \n");

    scanf("%d", &b);

    if(a>b){

        x=a;

    }

    else if(b>a){

        x=b;

    }

    again:

        if((x%a==0)&&(x%b==0)){

        printf("LCM is %d \n", x);

        }

        else{

            x=x+1;

            goto again;

        }

        return 0;

}